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find the equation (in terms of x) of the line through the points (-2,1) and(2,9)
Y=

Sagot :

RNashmi15

Answer:

2

Step-by-step explanation:

gradient =y² -y¹ /x²-x¹

=9-1/2--2

=8/4

=2

Answer:

y = 2x + 5

Step-by-step explanation:

There are 2 ways to find this equation:

The first way:  We have: y = ax + b (this is the line, right?)

The line is through the point (-2, 1) so we have:

1 = (-2)a + b      (1)

The line is also through the point (2, 9) so we have:

9 = 2a + b.       (2)

From (1) and (2) we get a equals 2, b equals 5. Then:
y = 2x + 5

The second way:

Let A(-2, 1) and B(2, 9), then AB = (4, 8).

=> The normal vector of this line is n = (-2, 1).

The line that is through the points A(-2, 1) and B(2, 9), and has the normal vector n=(-2, 1) has the equation:

[tex]-2(x - 2) + 1(y - 9) = 0[/tex]

[tex]-2x + y - 5 =0\\ < = > y = 2x + 5[/tex]


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