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Sagot :
[tex]\mathsf\blue{♧ANSWER♧}[/tex]
[tex] \mathsf \orange{ \frac{x \times y}{2}} [/tex]
[tex] \mathsf \green{ \frac{8 \times 12}{2} }[/tex]
[tex] \mathsf \orange{ \frac{96}{2} }[/tex]
[tex] \mathsf \green{48 \: square \: units}[/tex]
[tex] \huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }[/tex]
[tex]\qquad\qquad\qquad \large\underline{ \boxed{ \sf{✰\: Information }}}[/tex]
★ Given
- ➣A quadrilateral ABCD shape (kite) with diagonals "AC" and "BD"
- ➣ diagonal BD is of 8units
- ➣ diagonal AC is of 12units
✜ Now let's see about ques ✜
- question is asking about to find area of kite with the above info
- soo we know that
[tex]{ \boxed{ ✟ \: \underline{ \boxed{ \sf \: Area \: of \: kite = \frac{ d_1 \times d_2}{2} \: or \blue{ \: \frac{1}{2} \times d_1 \times d_2}}}✟ }}[/tex]
[tex]\rule{80mm}{2.5pt}[/tex]
✜ Let's substitute value according to formula ✜
[tex] \qquad \rm{➛Area \: of \: kite = \frac{BD×AC}{2} }[/tex]
[tex]\qquad \rm{➛Area \: of \: kite = \frac{8×12}{2} } \\ \qquad \rm{➛Area \: of \: kite = \frac{ \cancel{96}}{ \cancel2} } \\ \qquad \rm{➛Area \: of \: kite = 48 {units}^{2} }[/tex]
[tex]\rule{80mm}{2.5pt}[/tex]
★Hence area of kite with diagonals BD = 8 units and AC = 12 units is
[tex]\qquad\qquad\qquad{ \boxed{↪ \underline{ \boxed{ \sf{\: 48 {units}^{2} \green✓ }}}↩}}[/tex]
[tex]\rule{80mm}{2.5pt}[/tex]
★ More info regarding this topic ★
- ➣ Quadrilateral:- A polygon with four sides,sum of it's interior angle is of 360⁰
- ➣ Kite is also a quadrilateral because of four sides.Kite is a quadrilateral which is proved Euclidean geometry.
[tex]\rule{80mm}{2.5pt}[/tex]
Hope it helps !
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