Answered

Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

solve the question in the picture​

Solve The Question In The Picture class=

Sagot :

Answer:

n = 7

Step-by-step explanation:

simplify the logs according to their bases

View image monoaudrey
semsee45

Answer:

n = 7

Step-by-step explanation:

[tex]\sf \log_4(64)^{n+1}=log_5(625)^{n-1}[/tex]

Change 64 to an exponent with base 4 and 625 to an exponent with base 5:

[tex]\implies \sf \log_4(4^3)^{n+1}=log_5(5^4)^{n-1}[/tex]

Using exponent rule [tex](a^b)^c=a^{bc}[/tex]

[tex]\implies \sf \log_4(4)^{3(n+1)}=log_5(5)^{4(n-1)}[/tex]

Using log rule:  [tex]\log_a(b^c)=c \log_a(b)[/tex]

[tex]\implies \sf 3(n+1)\log_4(4)}=4(n-1)log_5(5)[/tex]

Using log rule: [tex]\sf \log_a(a)=1[/tex]

[tex]\implies \sf 3(n+1)=4(n-1)[/tex]

[tex]\implies \sf 3n+3=4n-4[/tex]

[tex]\implies \sf 3+4=4n-3n[/tex]

[tex]\implies \sf n=7[/tex]

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.