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Suppose that a car's starter motor draws 221 A of current for 6.20 s to start the car. What mass of Pb is oxidized in the lead–acid battery to supply this much electricity?

1.47 grams
Actually, I figured it out., here is the answer in case anyone is wondering:
It has two electrons in the process and Q is 1370.2 (Q= I*T= 221*6.2=1370.2) this gets to 1370.2/192736 (the number on the denominator is due to that fact that there are two electrons involved) That equals 0.007 Mols, and then using the grams per mol from the periodic table for lead, we get that value is equal to 1.47 grams.

Sagot :

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The lead acid battery produces energy by oxidation of lead. The amount of lead oxidized in this case is 1.47 g.

What is lead acid battery?

The lead acid battery is the common accumulator that we have in use. It is made up of a cell that contains lead electrodes in an acid.

The oxidation of lead occurs according to thr equation;

Pb(s) ----> Pb^2+(aq) + 2e

If 207 g of Pb is oxidized by 2(96500)C

x g of lead is oxidized by (221 * 6.20) C

x = 207 g * (221 * 6.20) C/2(96500)C

x = 1.47 g

Learn more about lead acid battery: https://brainly.com/question/8341588

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