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Suppose that y varies inversely with x. Write a function that models the inverse function.

x = 6 when y = 8

Sagot :

y=k/x
8=k/6
k=48
:y=48/x
GʀɪᴍRᴇᴀᴘᴇʀ

[tex] \qquad \qquad \huge\text{Anѕwer}♨[/tex]

Let's Solve ~

❖ Aѕ givєn in thє quєѕtiσn, ч vαriєѕ invєrѕєlч with х, thiѕ єхprєѕѕiσn cαn вє rєprєѕєntєd αѕ :

[tex] \qquad \Rrightarrow \rm y \propto \dfrac{1}{x} [/tex]

➻ To rєplαcє prσpσrtiσnαlitч ѕign with єquαlѕ tσ, wє hαvє tσ uѕє α cσnѕtαnt (k)

[tex] \qquad \Rrightarrow \rm y = k \times\dfrac{1}{x} [/tex]

[tex] \qquad \Rrightarrow \rm \dfrac{}{} xy = k[/tex]

➻ nσw, plug in vhє vαluєѕ σf х αnd ч fσr α ѕpєcific inѕtαnt, thαt'ѕ givєn in thє quєѕtiσn ~

  • х = 6, whєn ч = 8

[tex] \qquad \Rrightarrow \rm \dfrac{}{} 6 \times 8 = k[/tex]

[tex] \qquad \Rrightarrow \rm \dfrac{}{} k = 48[/tex]

thєrєfσrє, vαluє σf prσpσrtiσnαlч cσnѕtαnt iѕ 48

➼ ѕσ, thє rєquirєd єхprєѕѕiσn will вє :

[tex] \qquad \Rrightarrow \rm \dfrac{}{} xy = 48[/tex]

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