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Find the area of the regular polygon. Give the answer to the nearest tenth.

hexagon with a side of 6 in.

Sagot :

BasketballEinstein

Answer:

[tex]\displaystyle 93,5\:in.^2 \approx A[/tex]

Step-by-step explanation:

[tex]\displaystyle \frac{3\sqrt{3}}{2}a^2 = A \hookrightarrow \frac{3\sqrt{3}}{2}6^2 = A \\ \frac{3\sqrt{3}}{2}[36] = A; 54\sqrt{3}\:[or\:93,530743609...] \\ \\ \boxed{93,5 \approx A}[/tex]

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