loneguy
Answered

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Evaluate the limit

[tex]\lim \limits_{x\to 0} \dfrac{\ln \left(1-\dfrac x4 \right) - (1-x)^{\tfrac 14} +1}{x^2}[/tex]

Sagot :

Answer:

1/16

Step-by-step explanation:

Place x=0 and you can see [tex]\frac{0}{0}[/tex] indefinitness. So you can apply the l'hosptial rule. Its basic you should

[tex]\lim_{x \to \ 0} \frac{g(x)}{f(x)} = \\[/tex]  [tex]lim_{x \to \ 0} \frac{g'(x)}{f'(x)}[/tex] so apply the derivative

[tex]\frac{\frac{1}{x-4} +\frac{1}{\sqrt[4]{(1-x})^3 } }{2x}[/tex] and replace the x=0 and you'll see same answer [tex]\frac{0}{0}[/tex] re-apply the l'hospital rule and answer

[tex]\frac{\frac{-1}{(x-4)^2} + \frac{3}{16\sqrt[4]{(1-x)^7} } }{2}[/tex] and replace the 0 you can see the answer [tex]\frac{1}{16}[/tex]

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