Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Write an equation (a) in slope-intercept form and (b) in standard form for the line passing through (1,8) and perpendicular to 3x + 5y = 1


Sagot :

Step-by-step explanation:

a) 2y = 3x + 4

b) given the perpendicular

3x + 5y = 1

5y = 1 - 3x

y = 1/5 - 3x/5

m¹ = -3/5

perpendicular

m¹m² = -1

-3m²/5 = -1

m² = 5/3

so (1,8)

x¹ = 1 y¹ = 8

m² = (y - y¹)/(x - x¹)

5/3 = (y - 8)/(x - 1)

5x - 5 = 3y - 24

3y - 5x + 5 - 24 = 0

3y = 19 + 5x

^^^^^^^^^^^^^^^^^^^^^^
View image rayshawn71
We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.