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For what value of x is the value of the square of the binomial 2x +3
is 9 greater than the value of the square of the binomial 2x -3?


Help For What Value Of X Is The Value Of The Square Of The Binomial 2x 3 Is 9 Greater Than The Value Of The Square Of The Binomial 2x 3 class=

Sagot :

Answer:

  x = 3/8

Step-by-step explanation:

The difference of the two squares can be found several ways. One way uses the "difference of squares" special form.

  a² -b² = (a -b)(a +b)

For the given squares, this is ...

  (2x +3)² -(2x -3)² = ((2x +3)-(2x -3))((2x +3) +(2x -3)) = 6(4x) = 24x

We want to find x that makes this difference be 9:

  24x = 9

  x = 9/24 = 3/8

For the value x = 3/8, the difference between the squares of the binomials will be 9.

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