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Sagot :
Answer:
- 49.9 years or 50 years later.
- At year : 2042
Explanation:
use compound interest formula: [tex]\sf \boxed{ \sf P ( \sf 1 + \dfrac{r}{100} )^n}[/tex]
[tex]\rightarrow \s \sf 10( 1 + \dfrac{1.4}{100} )^n = 20[/tex]
[tex]\rightarrow \sf ( 1.014) ^n = 2[/tex]
[tex]\rightarrow \sf n( ln( 1.014) ) = ln(2)[/tex]
[tex]\rightarrow\sf n = \dfrac{ln(2)}{ln( 1.014)}[/tex]
[tex]\rightarrow\sf n = 49.8563 \ years[/tex]
Answer:
General form of an exponential equation: [tex]y=ab^x[/tex]
where:
- a is initial value
- b is the base (or growth factor in decimal form)
- x is the independent variable
- y is the dependent variable
- If b > 1 then it is an increasing function
- If 0 < b < 1 then it is a decreasing function
- Also b ≠ 0
Given information:
- initial population = 10 million
- growth rate = 1.4% each year
⇒ growth factor = 100% + 1.4% = 101.4% = 1.014
Inputting these values into the equation:
[tex]\implies y=10(1.014)^x[/tex]
where y is the population (in millions) and x is the number of years since 1992
Now all we need to do is set y = 20 and solve for x:
[tex]\implies 10(1.014)^x=20[/tex]
[tex]\implies 1.014^x=2[/tex]
[tex]\implies \ln 1.014^x=\ln 2[/tex]
[tex]\implies x\ln 1.014=\ln 2[/tex]
[tex]\implies x=\dfrac{\ln 2}{\ln 1.014}[/tex]
[tex]\implies x=49.85628343...[/tex]
1992 + x = 2041.8562....
Therefore, the population will reach 20 million during 2041, so the population will reach 20 million by 2042.
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