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Use the standard normal distribution to find P(-1.23 Sz<2.12).


Use The Standard Normal Distribution To Find P123 Szlt212 class=

Sagot :

Answer:

  (d)  0.8736

Step-by-step explanation:

Unless you have a table of the normal distribution available, this is a calculator problem. Your calculator, or any spreadsheet, can tell you the probability is ...

  P(-1.23 ≤ z ≤ 2.12) ≈ 0.8736

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