Answered

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What is the equation of a circle with center (−5, −8) and radius 2?

(x − 5)2 + (y − 8)2 = 4

(x + 5)2 + (y + 8)2 = 4

(x + 5)2 + (y + 8)2 = 2

(x − 5)2 + (y − 8)2 = 2

Sagot :

DᴀʀᴋPᴀʀᴀᴅᴏx

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Standard equation of circle ~

[tex]\qquad \sf  \dashrightarrow \:(x - h) {}^{2} + (y - k) {}^{2} = r {}^{2} [/tex]

where,

  • h = x - coordinate of centre

  • k = y - coordinate of centre

  • r = radius of the circle

Now, let's plug in the values ~

[tex]\qquad \sf  \dashrightarrow \:(x - (5)) {}^{2} + (y - ( - 8)) {}^{2} = {2}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:(x + 5) {}^{2} + (y + 8) {}^{2} = {4}^{} [/tex]

Therefore, the correct choice is B

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MrRoyal

The equation of the circle with a center of (4,5) and a radius of 2 units is (x + 5)² +(y + 8)² = 4

How to determine the circle equation?

The center of the circle is given as:

Center (a,b) = (-5, -8)

The radius is given as:

Radius, r = 2

The equation of the circle is calculated using:

(x - a)² + (y - b)² = r²

Substitute values for r and (a,b)

(x + 5)² +(y + 8)² = 2²

Evaluate the square of 2

(x + 5)² +(y + 8)² = 4

Hence, the equation of the circle is (x + 5)² +(y + 8)² = 4

Read more about circle equations at:

https://brainly.com/question/1559324

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