Answer:
As Per Provided Information
An ellipse has a vertex at (0, −7), a co-vertex at (4, 0), and a center at the origin (0,0) .
We have been asked to find the equation of the ellipse in standard form .
As we know the standard equation of an ellipse with centre at the origin (0,0). Since its vertex is on y-axis
[tex] \underline\purple{\boxed{\bf \: \dfrac{ {y}^{2} }{ {a}^{2} } \: + \: \dfrac{ {x}^{2} }{ {b}^{2} } = \: 1}}[/tex]
where,
Substituting these values in the above equation and let's solve it
[tex] \qquad\sf \longrightarrow \: \dfrac{ {y}^{2} }{ {( - 7)}^{2} } \: + \dfrac{ {x}^{2} }{ {(4)}^{2} } = 1 \\ \\ \\ \qquad\sf \longrightarrow \: \dfrac{ {y}^{2} }{49} \: + \frac{ {x}^{2} }{16} = 1 \\ \\ \\ \qquad\sf \longrightarrow \: \: \dfrac{ {x}^{2} }{16} \: + \dfrac{ {y}^{2} }{49} = 1[/tex]
Therefore,
- Required standard equation is x²/16 + y²/16 = 1
So, your answer is 2nd Picture.
