Answer:
7 units
Step-by-step explanation:
(Background info, skip if not interested or needed for you)
The equation for distance on a cartesian plane coordinate system is based off the pythagorean theorem.
[tex]a^2 + b^2 = c^2[/tex]
a and b being sides of a right triangle, c being the hypotenuse.
When we are solving for distance we are solving for c essentially.
[tex]c[/tex] = [tex]\sqrt{a^2 + b^2}[/tex]
Because a and b are side lengths of the right triangle, we need to find a way to find that in terms of coordinates. So here we might say that a is equal to the horizontal distance between the 2 points or Δx, and we would say that b is the vertical distance between the 2 points Δy.
(solutions)
So essentially distance is:
[tex]d = \sqrt{(x_2 - x_1)^2+ (y_2-y_1)^2 }[/tex]
Now we just use the values given to us, and sub in the x and y values respectively.
(-2,4) [tex]x_1 = -2, y_1 = 4[/tex]
(5,4)[tex]x_2 = 5, y_2 = 4[/tex]
plug these values in:
[tex]d = \sqrt{((5) - (-2))^2+ (4-4)^2 } = \sqrt{(7)^2+ (0)^2 } = \sqrt{7^2 } = 7[/tex]
Therefore the distance is 7 units.
