Ineedhelpinalgebra
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solve linear systems by multiplying
3x+y=-15
2x-3y=23
​

Sagot :

Lenvy

Answer:

x=-2, y=-9

Step-by-step explanation:

Given that:

[tex]\begin{bmatrix}3x+y=-15\\ 2x-3y=23\end{bmatrix}[/tex]

Solution:

[tex]\mathrm{Isolate\;x\;for\;3x+y=-15:x=\frac{-15-y}{3}}[/tex]

[tex]\mathrm{Substitute\:}x=\frac{-15-y}{3}[/tex]

[tex]\begin{bmatrix}2\cdot \frac{-15-y}{3}-3y=23\end{bmatrix}[/tex]

Simplify to:

[tex]\begin{bmatrix}\frac{-30-11y}{3}=23\end{bmatrix}[/tex]

[tex]\mathrm{Isolate\;y\;for\;\frac{-30-11y}{3}=23:y=-9}[/tex]

[tex]\mathrm{For\:}x=\frac{-15-y}{3}[/tex]

[tex]\mathrm{Substitute\:}y=-9[/tex]

[tex]x=\frac{-15-\left(-9\right)}{3}[/tex]

Solve:

[tex]x=-2[/tex]

Hence the answer is:

[tex]x=-2,\:y=-9[/tex]

~lenvy~

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