Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

A man tries to push a 200 kg Car that moves at a acceleration 0.50 m/s2. The man is able to displace the car 10 m. How much work did he do?

Sagot :

nuhulawal20

The work done by the man pushing the car over the given distance is 1000J.

Given the data in the question;

  • Mass of car; [tex]m = 200kg[/tex]
  • Acceleration of the car; [tex]a = 0.5m/s^2[/tex]
  • Distance covered by the car; [tex]d = 10m[/tex]

Work done; [tex]W = \ ?[/tex]

Work done

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

[tex]Work\ done = f * d[/tex]

Where f is force applied and d is distance travelled.

To determine the work done by the man, we first solve for the force applied F.

From Newton's Second Law; [tex]Force \ F = m * a[/tex]

We substitute our given values into the expression

[tex]F = m * a \\\\F = 200kg * 0.5m/s^2\\\\F = 100kg.m/s^2[/tex]

Next we substitute our values into the expression of work done above.

[tex]Work \ done = f * d\\\\Work \ done = 100kg.m/s^2 * 10m\\\\Work \ done = 1000kgm^2/s^2\\\\Work \ done = 1000J[/tex]

Therefore, the work done by the man pushing the car over the given distance is 1000J.

Learn more about work done: https://brainly.com/question/26115962

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.