Answer: -3x-2y+1
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Explanation:
In the first parenthesis grouping, we have these three terms
[tex]9x^2y[/tex]
[tex]6xy^2[/tex]
[tex]-3xy[/tex]
and we're dividing each of them over the denominator -3xy.
Think of it like the distributive property. In fact, division is a disguised version of multiplication, which is why the distributive property is not a coincidence. Example: 10/2 = 10*(1/2) = 10*0.5 = 5
If we divide each term over -3xy, then we get these three separate results:
[tex](9x^2y) \div (-3xy) = -3x[/tex]
[tex](6xy^2) \div (-3xy) = -2y[/tex]
[tex](-3xy) \div (-3xy) = 1[/tex]
The last equation is probably self explanatory: any number divided by itself is 1, as long as the number isn't zero. Eg: 4/4 = 1.
The first two equations might not be obvious. For the first equation, we divide the coefficients 9 and -3 to get -3 as the final coefficient on the right hand side. Then the variable terms cancel when pairing them up. Check out the diagram below to see what I mean by this canceling. It's optional, but it might help to think of [tex]x^2[/tex] as [tex]x*x[/tex]
A similar situation happens in the second equation as well.
After doing those three division operations, we then add up the results to arrive at -3x+(-2y)+1 which is the same as -3x-2y+1
