col7kings
Answered

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A 1500kg car moving at a speed of 20.1m/s comes toa stop after travelling a distance of 200m. What was the average force exerted by the breaks on the car?​

Sagot :

col8kings

Answer:

= -1515N

Explanation:

v^2=u^2+2as

0m/s

u=20.1m/s

0=(20.1)^2+(2xax200)

0=404.01+400a

-404.01=400a

-404.01÷400=a

a= -1.01m/s^s

its negative because the force is slowing down the car

Newton's second law of motion

F=ma

=1500×-1.01

F= -1515N

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