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P1 = (1,5). P2 = (x,2) .p1p2=5 ​

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DᴀʀᴋPᴀʀᴀᴅᴏx

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's use distance formula :

[tex]\qquad \sf  \dashrightarrow \: \sqrt{(x - 1) {}^{2} + (2 - 5) {}^{2} } = 5[/tex]

[tex]\qquad \sf  \dashrightarrow \: {(x - 1) {}^{2} + ( - 3) {}^{2} } = 5 {}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:(x - 1) {}^{2} + 9 = 25[/tex]

[tex]\qquad \sf  \dashrightarrow \:(x - 1) {}^{2} = 16[/tex]

[tex]\qquad \sf  \dashrightarrow \:(x - 1) = 16[/tex]

[tex]\qquad \sf  \dashrightarrow \:(x - 1) = \pm4[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 5 \: \: or \: \: - 3[/tex]

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