Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Bag A contains 5x coins.
Bag B contains 3x coins.
8 coins are taken from Bag B and put into Bag A
The ratio of coins in Bag A to Bag B is now 11:5
Work out the total number of coins.

Sagot :

MidnightShowers

Answer:

given ,

number of coins in bag A = 5x

number of coins in bag B = 3x

_____________________________________

According to Question ,

8 coins are taken from Bag B and put into Bag A

The ratio of coins in Bag A to Bag B is now 11 : 5

therefore ,

[tex] \frac{5x + 8}{3x - 8} = \frac{11}{5} \\ \\ 5(5x + 8) = 11(3x - 8) \\ \\ 25x + 40 = 33x - 88 \\ \\ 33x - 25x = 40 + 88 \\ \\ 8x = 128 \\ \\ x = \cancel\frac{128}{8} \\ \\ \fbox{x =16} [/tex]

now ,

[tex]no. \: of \: coins \: in \: bag \: A = 5x \\ \dashrightarrow{5 \times 16 = 80 \: coins}[/tex]

[tex]number \: of \: coins \: in \: bag \: B = 3x \\ \dashrightarrow{3 \times 16 = 48 \: coins}[/tex]

[tex]total \: number \: of \:coins = 80 + 48 \\ \dashrightarrow{ 128 \: coins}[/tex]

hope helpful :D

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.