Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

A tree is 18 feet tall and casts a shadow
that is 22 feet long. How far is it from the
end of the shadow to the top of the tree?
Show your work.


Sagot :

Answer:

28.42 feet

Step-by-step explanation:

Given

  • Height of tree = 18 feet
  • Length of shadow = 22 feet

To Find

  • Distance b/w top of tree and end of shadow

Solving

  • This resembles a right triangle
  • ⇒ We can use Pythagorean Theorem!
  • ⇒ 18² + 22² = L²
  • ⇒ L² = 324 + 484
  • ⇒ L² = 808
  • ⇒ L = 2√202
  • ⇒ L = 2 x 14.21
  • ⇒ L = 28.42 feet

Answer:

28.4 feet

Step-by-step explanation:

The question can be solved by using Pythagoras Theorem.

Given:-

Height of tree :- 18 feet (Perpendicular)

length of shadow :- 22 feet (Base)

To find:-

Distance of shadow from the end to the top of the tree

Solution:-

We know the Pythagoras theorem,

Which is , H² = P² + B²

So putting the given value , we get

H² = 18²+22²

H² = 324 + 484

H = √ 808 feet

H = 28.4 feet