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Sagot :
Answer:
41
Step-by-step explanation:
For this, you have to make two equations;
One that calculates the amount of coins
and one that calculates the amount of R
I'm going to set
R2 = x
R5 = y
To make this a bit easier to look at
So to do the number of coins, you want to do this:
x + y = 114
This is saying that the total amount of R2 coins plus the total amount of R5 coins will add up to 114
Then, you want to calculate the worth of them.
2(x) + 5(y) = 351
This is saying that for ever R2 coin there is, it will increase the total by 2, and every R5, it will increase the total by 5. When you add these together, it will come out to 351.
Then you have to solve the system of equations:
x + y = 114
2x + 5y = 351
-2 * (x + y = 114)
2x + 5y = 351
-2x + -2y = -228
2x + 5y = 351
3y = 123
y = 41
Since y is the amount of R5 coins, we know we have 41 R5 coins.
So the answer is
41
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