Answered

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Find the greatest possible number of consecutive zeros at the end of the product of three positive integers if the sum of these three integers equals 939.

Sagot :

Answer:

I think its 5 consecutive zeros.

Step-by-step explanation:

This would be a guess but I think you would need two numbers in the hundreds that also have 2 parts of which have a product of a number ending in 0, like 4 and 5.

So my guess would be

400 * 500 * 39

= 7800000

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