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find the equation of line that is parallel to another line whose equation is 8y+5x-6=0and passes through the point (8,5)

write down the equation of line perpendicular to y=7x/4+9/4 and passes through the origin

today is the deadline please help me

Sagot :

naj7499

Answer:

1) y= -5x/8 + 10 2)y= -4x/7

MIK0

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Answer:

1. x: x= 6−8y/5

  y: y=− 5x/8 + 3/4

2. x: x= 4y−9/7

   y: y= 7x+9/4

Explanation and Step:

[8y+5x-6=0]

* Subtract 5x from both sides. Anything subtracted from zero gives its negation.

* Add 6 to both sides.

* The equation is in standard form.

* Divide both sides by 8

* Dividing by 8 undoes the multiplication by 8.

* Divide −5x+6 by 8

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[y=7x/4+9/4]

* Since 7x/4 and 9/4 have the same denominator, add them by adding their numerators.

* Divide each term of 7x+9 by 4 to get 7/4 x + 9/4.

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