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CAN SOMEONE PLEASE HELP ITS DUE TODAY

CAN SOMEONE PLEASE HELP ITS DUE TODAY class=

Sagot :

Answer:

n = 6

Step-by-step explanation:

[tex] \frac{ {5}^{n} \times {5}^{3} }{ {5}^{7} } = {5}^{2} \\ \\ \implies \: \frac{ {5}^{n + 3} }{ {5}^{7} } = {5}^{2} \\ \\ \implies \: {5}^{n + 3 - 7} = {5}^{2} \\ \\ \implies \: {5}^{n - 4} = {5}^{2} \\ \\ \implies \:n - 4 = 2 \\ \\ \implies \:n = 4 + 2 \\ \\ \implies \:n = 6[/tex]

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's solve ~

[tex]\qquad \sf  \dashrightarrow \: \frac{5 {}^{n} \times {5}^{3} }{5 {}^{7} } = {5}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \frac{5 {}^{n + 3} {}^{} }{5 {}^{7} } = {5}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:5 {}^{n + 3 - 7} = {5}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:5 {}^{n - 4} = {5}^{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:{}{n - 4} = {2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:n = 2 + 4[/tex]

[tex]\qquad \sf  \dashrightarrow \:n = 6[/tex]

Hence, value of n is 6