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A rectangle is 12m longer than it is wide its perimeter is 68 find its length and width

Sagot :

konrad509
[tex]l=w+12\\ 2l+2w=68\\\\ 2(w+12)+2w=68\\ 2w+24+2w=68\\ 4w=44\\ w=11\\\\ l=11+12\\ l=23[/tex]

The length and width of the rectangle are 23 m and 11 m.

Given,

A rectangle is 12m longer than it is wide.

Its perimeter is 68.

We need to find its length and width.

What is a rectangle?

A rectangle is a quadrilateral with four sides and four angles where the opposite sides are equal and parallel and the angles are right-angled.

Area of a rectangle = Length x Width.

Perimeter of a rectangle = 2 ( Length + Width ).

We have,

A rectangle is 12m longer than it is wide.

Let length = L and wide = W.

We can write it as,

L = 12 + W.

We have,

Its perimeter is 68.

Let P be the perimeter of the rectangle.

P = 2 ( L + W )

68 = 2 ( L + W )

68 / 2 = L + W

34 = L + W

Putting L = 12 + W

We get,

34 = 12 + W + W

34 = 12 + 2W

34 - 12 = 2W

22 = 2W

W = 11 m.

Putting W = 11 in L = 12 + W.

We get,

L = 12 + 11

L = 23 m.

Thus, the Length and Width of the rectangle are 23 m and 11 m.

Learn more about rectangles here:

https://brainly.com/question/15019502

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