Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
[tex]l=w+12\\
2l+2w=68\\\\
2(w+12)+2w=68\\
2w+24+2w=68\\
4w=44\\
w=11\\\\
l=11+12\\
l=23[/tex]
The length and width of the rectangle are 23 m and 11 m.
Given,
A rectangle is 12m longer than it is wide.
Its perimeter is 68.
We need to find its length and width.
What is a rectangle?
A rectangle is a quadrilateral with four sides and four angles where the opposite sides are equal and parallel and the angles are right-angled.
Area of a rectangle = Length x Width.
Perimeter of a rectangle = 2 ( Length + Width ).
We have,
A rectangle is 12m longer than it is wide.
Let length = L and wide = W.
We can write it as,
L = 12 + W.
We have,
Its perimeter is 68.
Let P be the perimeter of the rectangle.
P = 2 ( L + W )
68 = 2 ( L + W )
68 / 2 = L + W
34 = L + W
Putting L = 12 + W
We get,
34 = 12 + W + W
34 = 12 + 2W
34 - 12 = 2W
22 = 2W
W = 11 m.
Putting W = 11 in L = 12 + W.
We get,
L = 12 + 11
L = 23 m.
Thus, the Length and Width of the rectangle are 23 m and 11 m.
Learn more about rectangles here:
https://brainly.com/question/15019502
#SPJ2
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.
