snitiser7
Answered

Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

PQ and QR are 2 sides of a regular 10-sided polygon
Can someone please help I've been struggling on this for quite a while.

PQ And QR Are 2 Sides Of A Regular 10sided Polygon Can Someone Please Help Ive Been Struggling On This For Quite A While class=

Sagot :

xenia168

Answer:

Step-by-step explanation:

Measure of inner angle of the n-sided polygon is

[tex]\frac{180(n-2)}{n}[/tex]

~~~~~~~~~~~~~~

m∠PQR = [tex]\frac{180(10-2)}{10}[/tex] = 144°

PQ = QR ⇒ m∠QPR = m∠QRP

m∠PRQ = ( 180° - 144° ) ÷ 2 = 18 °

semsee45

Answer:

∠PRQ = 18°

Step-by-step explanation:

Sum of interior angles of a polygon = (n - 2) × 180°
(where n is the number of sides)

Interior angle of a regular polygon = sum of interior angles ÷ n
(where n is the number of sides)

Given:

  • n = 10

⇒ Sum of interior angles of a polygon = (10 - 2) × 180° = 1440°

⇒ Interior angle of a regular polygon = 1440° ÷ 10 = 144°

Therefore, as PQ and QR are the sides of the polygon, ∠PQR = 144°

Sum of interior angles of a triangle = 180°

⇒ ∠PQR + ∠RPQ + ∠PRQ = 180°

⇒ 144° + ∠RPQ + ∠PRQ = 180°

⇒ ∠RPQ + ∠PRQ = 36°

As the polygon is regular, PQ = QR which means that ΔPQR is isosceles.

Therefore, ∠RPQ = ∠PRQ

⇒ ∠PRQ = 36° ÷ 2 = 18°

We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.