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Sagot :
The launching of the hot air balloon is from the ocean beach is an illustration of a projectile motion
The horizontal distance which it attains a maximum height
The function is given as:
[tex]p(x) =-\frac{2}{2500}x^2 + 0.7x[/tex]
Differentiate
[tex]p'(x) =-\frac{4}{2500}x + 0.7[/tex]
Set to 0
[tex]-\frac{4}{2500}x + 0.7 = 0[/tex]
Subtract 0.7 from both sides
[tex]-\frac{4}{2500}x =- 0.7[/tex]
Multiply through by -2500/4
[tex]x =437.5[/tex]
Hence, the horizontal distance which a maximum height is attained is 437.5 meters
The maximum height above the sea level
In (a), we have:
[tex]x =437.5[/tex]
Substitute [tex]x =437.5[/tex] in p(x)
[tex]p(437.5) =-\frac{2}{2500} * 437.5^2 + 0.7 * 437.5[/tex]
Evaluate
[tex]p(437.5) =153.125[/tex]
Hence, the maximum height above the sea level is 153.125 metres
The maximum height above the ground level
In (b), the maximum height above the sea level is 153.125 metres
The ratio of the height on land and sea is given as:
Land : Sea = 2 m : 20 m
For the maximum height, we have:
Land : 153.125 m= 2 m : 20 m
Express as fraction
Land / 153.125 m = 2 /20
Multiply both sides by 153.125
Land = 15.3125
Approximate
Land = 15.3
Hence, the maximum height above the ground level is 15.3 meters
The horizontal distance where the balloon 50 m above the ground
We have:
[tex]p(x) =-\frac{2}{2500}x^2 + 0.7x[/tex]
Substitute 50 for P(x)
[tex]-\frac{2}{2500}x^2 + 0.7x = 50[/tex]
Using a graphing calculator, we have:
x = 78.465 and 796.535
Hence, the horizontal distances where the balloon 50 m above the ground are 78.465 and 796.535 meters
Read more about projectile motion at:
https://brainly.com/question/1130127
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