seayelana3
Answered

At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

compound has a percent composition of 38.7% carbon, 9.76% hydrogen, 51.5% oxygen.
Laboratory data shows that the compound's molar mass is 62.0 g/mol. What is the
molecular formula of the compound?

Sagot :

dsdrajlin

The molecular formula for a compound with a percent composition of 38.7% C, 9.76% H, 51.5% O, and a molar mass of 62.0 g/mol is C₂H₆O₂.

What is a molecular formula?

A molecular formula is a chemical formula indicating the kinds and number of atoms of each kind in a molecule of a compound.

To determine the molecular formula, we need to follow a series of steps.

  • Step 1. Divide the percentage of each element by its molar mass.

C: 38.7/12.01 = 3.22

H: 9.76/1.01 = 9.66

O: 51.5/16.00 = 3.22

  • Step 2. Divide all the numbers by the smallest one, i.e. 3.22.

C: 3.22/3.22 = 1

H: 9.76/3.22 = 3

O: 3.22/3.22 = 1

The empirical formula is CH₃O and its molar mass is 31.04 g/mol.

  • Step 3. Determine the molecular formula.

First, we will calculate how many times the empirical formula is contained in the molecular formula by dividing their molar masses.

n = (62.0 g/mol) / (31.04 g/mol) = 2

The molecular formula is 2 times the empirical formula, that is, C₂H₆O₂.

The molecular formula for a compound with a percent composition of 38.7% C, 9.76% H, 51.5% O, and a molar mass of 62.0 g/mol is C₂H₆O₂.

Learn more about molecular formulas here: https://brainly.com/question/26388921

We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.