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(10) The population of bacteria an experiment can be modeled by d p(d)= 400(1.56)^d , where d is the number of days the population has been growing.

(a) Find the average rate the population has been growing over the interval 0≤d≤7.
Round to the nearest integer and include appropriate units.

(b) If the population of bacteria was modeled as a function of the number of hours, h,
such that h p(h)= 400b^h then what would be the value of b to the nearest thousandth?
Show or explain how you found your answer.

Sagot :

raphealnwobi

The average rate at which the population is growing over the interval 0≤d≤7 is 1228, while the exponential function as a function of hours is [tex]p(h)=400(1.56)^{\frac{h}{24} }[/tex]

What is an exponential function?

An exponential function is in the form:

y = abˣ

Where a is the initial value and b is the multiplication factor.

Let p represent the population of the bacteria after d days.

[tex]P(d)=400(1.56)^d\\\\P(7)=400(1.56)^7=8994\\\\P(0)=400\\\\\\Average\ rate\ of\ change=\frac{P(7)-P(0)}{7-0}=\frac{8994-400}{7-0} =1228[/tex]

b) 24 hours = 1 day, hence:

[tex]p(h)=400(1.56)^{\frac{h}{24} }[/tex]

The average rate at which the population is growing over the interval 0≤d≤7 is 1228, while the exponential function as a function of hours is [tex]p(h)=400(1.56)^{\frac{h}{24} }[/tex]

Find out more on exponential function at: https://brainly.com/question/12940982

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