destiny11610
Answered

Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

can someone help me with this question

Can Someone Help Me With This Question class=

Sagot :

semsee45

Answer:

B

Step-by-step explanation:

Convert from mixed numbers to improper fractions:

[tex]\sf area=90 \frac{3}{10}=\dfrac{90 \cdot 10+3}{10}=\dfrac{903}{10}[/tex]

[tex]\sf length=10\frac12=\dfrac{10 \cdot 2+1}{2}=\dfrac{21}{2}[/tex]

Area of a rectangle = length x width

⇒ width = area ÷ length

[tex]\sf \implies width=\dfrac{903}{10} \div \dfrac{21}{2}[/tex]

[tex]\sf \implies width=\dfrac{903}{10} \times \dfrac{2}{21}[/tex]

[tex]\sf \implies width=\dfrac{1806}{210}[/tex]

[tex]\sf \implies width=\dfrac{1806 \div 42}{210 \div 42}[/tex]

[tex]\sf \implies width=\dfrac{43}{5}[/tex]

[tex]\sf \implies width=8\frac35[/tex]

WindyMint

[tex] \pink{ \text{Given:}}[/tex]

[tex] \\ [/tex]

[tex] \star \sf{}Area =90 \dfrac{3}{10} [/tex]

[tex] \\ [/tex]

[tex] \star \sf{}Length =10 \dfrac{1}{2} [/tex]

[tex] \\ \\ [/tex]

[tex] \purple{ \text{To~Find:}}[/tex]

[tex] \\ \\ [/tex]

[tex] \star \sf Width \: of \: rectangle[/tex]

[tex] \\ \\ [/tex]

[tex] \orange{ \text{Solution:}}[/tex]

[tex] \\ \\ [/tex]

So first convert length and area from fraction form to decible.

[tex] \leadsto\sf{}Area =90 \dfrac{3}{10} [/tex]

[tex] \\ [/tex]

[tex] \leadsto\sf{}Area = \dfrac{903}{10} [/tex]

[tex] \\ [/tex]

[tex] \leadsto\sf{}Area =90.3[/tex]

[tex] \\ [/tex]

Now convert value length into decibel .

[tex] \\ [/tex]

[tex] \leadsto\sf{}Length =10 \dfrac{1}{2} [/tex]

[tex] \\ [/tex]

[tex] \leadsto\sf{}Length = \dfrac{21}{2} [/tex]

[tex] \\ [/tex]

[tex] \leadsto\sf{}Length = 10.5[/tex]

[tex] \\ [/tex]

We know :-

[tex]\bigstar\boxed{\rm Area~of~rectangle= length \times width}[/tex]

[tex] \\ \\ [/tex]

So:-

[tex] \\ [/tex]

[tex]: \implies\sf Area~of~rectangle= length \times width \\ \\ \\ : \implies\sf 90.3= 10.5 \times width \\ \\ \\: \implies\sf 90.3 \div 10.5=width \\ \\ \\: \implies\sf \dfrac{ 90.3}{10.5}=width \\ \\ \\: \implies\sf \dfrac{ 90 \cancel.3}{10 \cancel.5}=width \\ \\ \\: \implies\sf \dfrac{ 903}{105}=width \\ \\ \\: \implies\sf width = \dfrac{ 903}{105} \\ \\ \\: \implies \underline{\boxed{\sf width = 8.6}} \pink\bigstar[/tex]

[tex]\\\\\\[/tex]

Know More:

[tex]\begin{lgathered}\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}\end{lgathered}[/tex]

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.