Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

can someone help me with this question

Can Someone Help Me With This Question class=

Sagot :

Answer:

B

Step-by-step explanation:

Convert from mixed numbers to improper fractions:

[tex]\sf area=90 \frac{3}{10}=\dfrac{90 \cdot 10+3}{10}=\dfrac{903}{10}[/tex]

[tex]\sf length=10\frac12=\dfrac{10 \cdot 2+1}{2}=\dfrac{21}{2}[/tex]

Area of a rectangle = length x width

⇒ width = area ÷ length

[tex]\sf \implies width=\dfrac{903}{10} \div \dfrac{21}{2}[/tex]

[tex]\sf \implies width=\dfrac{903}{10} \times \dfrac{2}{21}[/tex]

[tex]\sf \implies width=\dfrac{1806}{210}[/tex]

[tex]\sf \implies width=\dfrac{1806 \div 42}{210 \div 42}[/tex]

[tex]\sf \implies width=\dfrac{43}{5}[/tex]

[tex]\sf \implies width=8\frac35[/tex]

[tex] \pink{ \text{Given:}}[/tex]

[tex] \\ [/tex]

[tex] \star \sf{}Area =90 \dfrac{3}{10} [/tex]

[tex] \\ [/tex]

[tex] \star \sf{}Length =10 \dfrac{1}{2} [/tex]

[tex] \\ \\ [/tex]

[tex] \purple{ \text{To~Find:}}[/tex]

[tex] \\ \\ [/tex]

[tex] \star \sf Width \: of \: rectangle[/tex]

[tex] \\ \\ [/tex]

[tex] \orange{ \text{Solution:}}[/tex]

[tex] \\ \\ [/tex]

So first convert length and area from fraction form to decible.

[tex] \leadsto\sf{}Area =90 \dfrac{3}{10} [/tex]

[tex] \\ [/tex]

[tex] \leadsto\sf{}Area = \dfrac{903}{10} [/tex]

[tex] \\ [/tex]

[tex] \leadsto\sf{}Area =90.3[/tex]

[tex] \\ [/tex]

Now convert value length into decibel .

[tex] \\ [/tex]

[tex] \leadsto\sf{}Length =10 \dfrac{1}{2} [/tex]

[tex] \\ [/tex]

[tex] \leadsto\sf{}Length = \dfrac{21}{2} [/tex]

[tex] \\ [/tex]

[tex] \leadsto\sf{}Length = 10.5[/tex]

[tex] \\ [/tex]

We know :-

[tex]\bigstar\boxed{\rm Area~of~rectangle= length \times width}[/tex]

[tex] \\ \\ [/tex]

So:-

[tex] \\ [/tex]

[tex]: \implies\sf Area~of~rectangle= length \times width \\ \\ \\ : \implies\sf 90.3= 10.5 \times width \\ \\ \\: \implies\sf 90.3 \div 10.5=width \\ \\ \\: \implies\sf \dfrac{ 90.3}{10.5}=width \\ \\ \\: \implies\sf \dfrac{ 90 \cancel.3}{10 \cancel.5}=width \\ \\ \\: \implies\sf \dfrac{ 903}{105}=width \\ \\ \\: \implies\sf width = \dfrac{ 903}{105} \\ \\ \\: \implies \underline{\boxed{\sf width = 8.6}} \pink\bigstar[/tex]

[tex]\\\\\\[/tex]

Know More:

[tex]\begin{lgathered}\small\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf \small{Formulas\:of\:Areas:-}}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}\end{gathered}\end{lgathered}[/tex]