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The following equation models the deer population during mating season starting April 1, 2016, where m is time in months.

1053(1.23)^m = N

(a) How many deer were there on April 1, 2016?

(b) How many deer were there on May 1, 2016?

(c) What is the monthly growth rate?

(d) What is the yearly growth rate?

(e) What is the weekly growth rate?

Sagot :

The function N =1053(1.23)^m or 1053(1.23)^m = N is an illustration of an exponential function

The deer on April 1, 2016

The function is given as:

N =1053(1.23)^m

On April 1, 2016; the value of m is:

m = 0

So, we have:

N =1053(1.23)^0

N = 1053

Hence, there are 1053 deers on April 1, 2016

The deer on May 1, 2016

The function is given as:

N =1053(1.23)^m

On April 1, 2016; the value of m is:

m = 1

So, we have:

N =1053(1.23)^1

N =1295

Hence, there are 1295 deers on May 1, 2016

The monthly growth rate

An exponential growth function is represented as:

y = a(1 + r)^x

Where r represents the growth rate

By comparison; the monthly growth rate (r) is calculated as:

1 + r = 1.23

Subtract 1 from both sides

r = 0.23

Express as percentage

r = 23%

Hence, the monthly growth rate is 23%

The yearly growth rate

We have the monthly growth rate to be 23%

There are 12 months in a year.

So, the yearly growth rate is:

y = 23%^12

Evaluate

y = 0.00022%

Hence, the yearly growth rate is 0.00022%

The weekly growth rate

We have the monthly growth rate to be 23%

There are 4 weeks in a months

So, the weekly growth rate is:

m = 23%^(1/4)

Evaluate

m = 69%

Hence, the weekly growth rate is 69%

Read more about exponential functions at:

https://brainly.com/question/11464095