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Sagot :
Digram:-
[tex] \\ [/tex]
[tex]\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\put(5,1){\vector(1,0){4}}\put(5,1){\vector(-1,0){4}}\put(5,1){\vector(1,1){3}}\put(2,2){$\underline{\boxed{\large\sf a + b = 180^{\circ}}$}}\put(4.5,1.3){$\sf a^{\circ}$}\put(5.7,1.3){$\sf b^{\circ}$}\end{picture}[/tex]
[tex] \\ [/tex]
STEP :-
[tex] \dashrightarrow \tt(4q - 1) {}^{ \circ} + {117}^{ \circ} = 18 {0}^{ \circ} [/tex]
{Linear pair}
[tex] \\ \\ [/tex]
[tex] \dashrightarrow \tt(4q - 1) {}^{ \circ}= 18 {0}^{ \circ} - {117}^{ \circ}[/tex]
[tex] \\ [/tex]
[tex] \dashrightarrow \tt(4q - 1) {}^{ \circ}=63^{ \circ}[/tex]
[tex] \\ [/tex]
[tex] \dashrightarrow \tt4q - 1{}^{ \circ}=63^{ \circ}[/tex]
[tex] \\ [/tex]
[tex] \dashrightarrow \tt4q =63^{ \circ} + 1{}^{ \circ}[/tex]
[tex] \\ [/tex]
[tex] \dashrightarrow \tt4q =64{}^{ \circ}[/tex]
[tex] \\ [/tex]
[tex] \dashrightarrow \tt \: q = \dfrac{64}{4}^{ \circ}[/tex]
[tex] \\ [/tex]
[tex] \dashrightarrow \tt \: q = \dfrac{16 \times 4}{4}^{ \circ}[/tex]
[tex] \\ [/tex]
[tex] \dashrightarrow \tt \: q = \dfrac{16 \times \cancel4}{\cancel4}^{ \circ}[/tex]
[tex] \\ [/tex]
[tex] \dashrightarrow \tt \: q = \dfrac{16}{1}[/tex]
[tex] \\ [/tex]
[tex] \dashrightarrow \bf q = 16 \degree[/tex]
[tex] \\ \\ [/tex]
Verification:
[tex] \\ [/tex]
[tex] \dashrightarrow \tt(4 \times 16- 1) {}^{ \circ} + {117}^{ \circ} = 18 {0}^{ \circ} [/tex]
[tex] \\ [/tex]
[tex] \dashrightarrow \tt(64- 1) {}^{ \circ} + {117}^{ \circ} = 18 {0}^{ \circ} [/tex]
[tex] \\ [/tex]
[tex] \dashrightarrow \tt63^{ \circ} + {117}^{ \circ} = 18 {0}^{ \circ} [/tex]
[tex] \\ [/tex]
[tex] \dashrightarrow \tt180^{ \circ} = 18 {0}^{ \circ} [/tex]
[tex] \\ [/tex]
LHS = RHS
HENCE VERIFIED!
Answer:
Value of [tex]\sf\purple{q\: = \:16.}[/tex]
Step-by-step explanation:
[tex]\rightarrow[/tex]As we know that,
Sum all angles that lie on a straight line = [tex]\sf\blue{180°}[/tex]
So,
[tex]\rightarrow[/tex] [tex]\sf{(4q-1)°+ 117°\: = \:180°}[/tex]
[tex]\rightarrow[/tex] [tex]\sf{(4q-1)\: = \:180-117}[/tex]
[tex]\rightarrow[/tex] [tex]\sf{(4q-1)\: = \:63}[/tex]
[tex]\rightarrow[/tex] [tex]\sf{4q\: = \:63+1}[/tex]
[tex]\rightarrow[/tex] [tex]\sf{q\: = \:\frac{64}{4}}[/tex]
[tex]\rightarrow[/tex] [tex]\sf{q\: = \:16}[/tex]
Thus, [tex]\sf\purple{q\: = \:16.}[/tex]
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