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If we have 100ml of water at 0 degrees Celsius and it all freezes, how much energy did the water lose? Using the formula Hfus = Q/n

Sagot :

The amount of heat energy lost by the 100 mL of water when it all freezes is 33400 J

Data obtained from the question

  • Volume of water = 100 mL
  • Heat (Q) =?

How to determine mass of water

  • Volume of water = 100 mL
  • Density of water = 1 g/mL
  • Mass of water =?

Mass = Density ×Volume

Mass of water = 1 × 100

Mass of water = 100 g

How to determine the heat

  • Mass of water = 100 g
  • Heat of fusion (ΔHf) = 334 J/g
  • Heat (Q) =?

Q = m × ΔHf

Q = 100 × 334

Q = 33400 J

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