s018092
Answered

Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

A glass container was initially charged with 1.95 moles of a gas sample at 3.75 atm and 21.7 °C. Some of the gas was released as the temperature was increased to 28.1 °C, so the final pressure in the container was reduced to 0.998 atm. What quantity in moles of the gas sample are present at the end?

Sagot :

Answer:

45830.4 moles

Explanation:

Ideal gas law is the hypothetical equation in which the pressure, volume, and temperature of the gas are directly related. It can be denoted as:

PV = nRT

The ideal gas law is:

PV = nRT

where,

P = Pressure

V = Volume

R = Gas constant

T =Temperature

n = moles

Given:

Moles in container = 1.95

Temperture = 294.85 K

Pressure = 3.75 atm

Volume =?

Substituting the values:

V = nRT/P

V = 1.95 × 0.082 × 294 / 3.75

Volume = 12.5 L

Now, the condition when changed, such that temperature is 301.25 K, pressure is 0.998 atm, and Volume is 12.5 L, then moles will be equal to:

PV/RT = n

0.998 × 12.5 / 0.082 × 301.25 = n

n = 45830.4 moles

Therefore, 0.521 moles is still present in the container.

To know more about ideal gas law, refer to the following link:

brainly.com/question/12124605

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.