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the legnth of a rectangle is three times its width. if the length of the perimeter is 64 in, find the length and width

Sagot :

Answer:

  • Length and width of rectangle is 24 and 8 inches

Step-by-step explanation:

Given:

  • Length of rectangle is three times the width
  • Perimeter of rectangle is 64 Inches

To Find:

  • Length and Width

Solution:

Let's assume Width of rectangle x inches and length be 3x inches. To calculate the dimensions of The rectangle we will use the formula of Perimeter of rectangle:

Perimeter of rectangle = 2(L + B)

→ 64 = 2(3x + x)

→ 64 = 2(4x)

→ 64/2 = 4x

→ 32 = 4x

→ 32/4 = x

→ 8 = x

Hence,

  • Length of the rectangle = 3x = 3(8) = 24 inches

  • Width of the rectangle = x = 8 inches

Answer:

  • Length = 24 inches

  • Width = 8 inches

Step-by-step explanation :

As it is given that, the legnth of a rectangle is three times its width and the perimeter is 64 in and we are to find the length and width of the rectangle. So,

Let us assume the width of the rectangle as w inches and therefore, the length will be 3w inches .

Now, According to the Question :

[tex]{\longrightarrow \qquad { \pmb{\frak {2 ( Length + Breadth )= Perimeter_{(Rectangle)} }}}}[/tex]

[tex]{\longrightarrow \qquad { {\sf{2 (3 x + x )= 64 }}}}[/tex]

[tex]{\longrightarrow \qquad { {\sf{2 (4x )= 64 }}}}[/tex]

[tex]{\longrightarrow \qquad { {\sf{8x= 64 }}}}[/tex]

[tex]{\longrightarrow \qquad { {\sf{ x = \dfrac{64}{8} }}}}[/tex]

[tex]{\longrightarrow \qquad{ \underline{ \boxed { \pmb{\mathfrak {x = 8}} }}} }\: \: \bigstar[/tex]

Therefore,

  • The width of the rectangle is 8 inches .

Now, We are to find the length of the rectangle:

[tex]{\longrightarrow \qquad{ { \frak{\pmb{Length = 3x }}}}}[/tex]

[tex]{\longrightarrow \qquad{ { \frak{\pmb{Length = 3 \times 8 }}}}}[/tex]

[tex]{\longrightarrow \qquad{ \underline{ \boxed{ \frak{\pmb{Length = 24}}}}}} \: \: \bigstar[/tex]

Therefore,

  • The length of the rectangle is 24 inches .