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For what values of x is x3+23x2+162x+360=0 a true statement?

Sagot :

Answer:

Step-by-step explanation:

x³+23x²+162x+360=0

x³+12x²+11x²+132x+30x+360=0

x²(x+12)+11x(x+12)+30(x+12)=0

(x+12)(x²+11x+30)=0

(x+12)[x²+6x+5x+30]=0

(x+12)[x(x+6)+5(x+6)]=0

(x+12)(x+6)(x+5)=0

x=-12,-6,-5

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