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Sagot :
Answer:
[tex]x\leq 4[/tex]
Step-by-step explanation:
Given:
[tex]-\frac{1}{2}x+8\ge 6[/tex]
Solve:
[tex]\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides}[/tex]
[tex]-\frac{1}{2}x+8-8\ge \:6-8[/tex]
[tex]\mathrm{Simplify}[/tex]
[tex]-\frac{1}{2}x\ge \:-2[/tex]
[tex]Multiply\:both\:sides\:by\:-1[/tex]
[tex]\left(-\frac{1}{2}x\right)\left(-1\right)\le \left(-2\right)\left(-1\right)[/tex]
[tex]\mathrm{Simplify}[/tex]
[tex]\frac{1}{2}x\le \:2[/tex]
[tex]\mathrm{Multiply\:both\:sides\:by\:}2[/tex]
[tex]2\cdot \frac{1}{2}x\le \:2\cdot \:2[/tex]
[tex]\mathrm{Simplify}[/tex]
[tex]x\leq 4[/tex]
[tex]\mathrm{Therefore,}[/tex]
[tex]\begin{bmatrix}\mathrm{Solution:}\:&\:x\le \:4\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:4]\end{bmatrix}[/tex]
~lenvy~
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