hoangpm04
Answered

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Step by Step solution please.
Thanks

Step By Step Solution Please Thanks class=

Sagot :

linandrew41

Derivation of f(x):

   [tex]f'(x) = \frac{g(x)*8x-4x^2*g'(x)}{(g(x))^2} -\frac{1}{x+2}[/tex]

    Since g(3) = 6 and g'(3) = 3

   [tex]f'(3) = \frac{g(3)*8*3-4(3)^2*g'(3)}{(g(3))^2} -\frac{1}{3+2} \\f'(3) = \frac{6*8*3-4*9*3}{36} -\frac{1}{5} \\f'(3) = \frac{36}{36} -\frac{1}{5} =1-\frac{1}{5} =\frac{4}{5}\\ f'(3) = 0.8[/tex]

Thus f'(3) = 0.8

Hope that helps!

A couple of identities I used in derivation:

[tex]\frac{d}{dx} (ln x) = \frac{1}{x}[/tex]

View image linandrew41
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