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An ideal gas exerts a pressure of 3atm in a 3L container. The container is at a temperature of 298K.

What will be the final pressure if the volume of the container changes to 2L?

Possible Answers:
4.5atm

2atm

4atm

3.5atm​

Sagot :

Ankit

Given:

Initial pressure P1 = 3 atm

Initial volume = 3L

Temperature (constant)= 298 K

final volume V2 = 2L

To find:

Final pressure P2 = ?

Solution:

According to Boyle's Law,

P1V1 = P2V2

3×3 = 2 × P2

P2 = 9/2

P2 = 4.5 atm

[tex]{Answer = 4.5 atm}[/tex]

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