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Sagot :
Answer:
[tex] \frac{4(x - 5)(x + 7)(x - 12)}{(x + 1)(x)(x - 12)} [/tex]
Step-by-step explanation:
A rational function is
[tex] \frac{p(x)}{q(x)} [/tex]
where q(x) doesn't equal zero.
If p is a asymptote, or hole at that value, then we will use
[tex](x - p)[/tex]
Step 1: We have asymptote as 0 and -1 so our denomiator will include
[tex](x - 0)(x - ( - 1)[/tex]
Which is
[tex](x)(x + 1)[/tex]
So our denomator so far is
[tex] \frac{p(x)}{x(x + 1)} [/tex]
Step 2: Find Holes.
Since 12 is the value of the hole,
[tex](x - 12)[/tex]
is a the binomial.
This will be both on the numerator and denomator so qe have
[tex] \frac{(x - 12)}{x(x + 1)(x - 12)} [/tex]
Step 3: Put the x intercepts in the numerator.
Since 5 and -7 is the intercepts,
[tex] \frac{(x - 12)(x - 5)(x + 7)}{x(x + 1)(x - 12)} [/tex]
Step 4: Horinzontal Asymptotes,
Multiply the numerator and denomiator out fully,
[tex] \frac{ {x}^{3} - 10 {x}^{2} - 59x + 420 }{ {x}^{3} - 12 {x}^{2} + x - 12} [/tex]
Take a L
look at the coefficients,
Notice they have the same degree,3, this means if we divide the leading coefficents, we will get our horinzonral asymptote.
Multiply the numerator by 4.
[tex] \frac{4(x - 12)(x - 5)(x - 7)}{x(x + 1)(x - 12)} [/tex]
Above is the function,
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