Based on the equation of the reaction and the limiting reactant of the reaction, molarities of the ions are determined from the amount in moles of excess reactants and soluble products formed.
What is the limiting reactant in the reaction?
The limiting reactant is he reavtant that is used up in the reaction after which the reaction stops.
The limiting reactant is obtained from the mole ratio of the reactants in the equation of the reaction.
Equation of reaction is given as follows:
- 3 AgNO3 (aq) + Na3P (aq) ----> Ag3P (s) + 3 NaNO3 (aq)
Molar mass of AgNO3 = 170 g/mol
Molar mass of Na3P = 100 g/mol
Molar mass of Ag3P = 355 g/mol
Molar mass of NaNO3 = 85 g/mol
Mass of AgNO3 reacting = 83.4 g
Moles of AgNO3 reacting = 83.4/170 = 0.49 moles
Mass of Na3P reacting = 62.9
Moles of Na3P reacting = 62.9/100 = 0.629 moles
Moles ratio of AgNO3 to Na3P = 3 : 1
Mole rational of AgNO3 and NaNO3 1 : 1
Based on the mole ratio;
- AgNO3 is the limiting reactant while Na3P is in excess
- Moles of Na3P left over is 0.629 - (1/3 × 0.49) = 0.465 moles
- 0.49 moles of NaNO3 are formed
At the end of the reaction, molarity of the ions are as follows:
Molarity of Na+ = {0.49 + (3 × 0.46)}/1.71
- Molarity of Na+ = 1.094 M
Molarity of P^{3+} = 0.465/1.71
- Molarity of P^{3+} = 0.272 M
Molarity of NO3^{-1} = 0.49/1.71
- Molarity of NO3^{-1} = 0.286 M
Therefore, molarities of the ions are determined from the amount in moles of excess reactants and soluble products formed.
Learn more about limiting reactant at: https://brainly.com/question/14225536
