Answered

Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Ask your questions and receive precise answers from experienced professionals across different disciplines. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Is (-6, -7) a solution to this system of equations?

y = 4x + 9
y = 2x + 5

Yes or no

Sagot :

Esther

Answer:

The answer is no

*View the attached graph to check your answer graphically.*

Step-by-step explanation:

y = 4x + 9

y = 2x + 5

For this problem, I will be using substitution, since the both equations are already in the slope-intercept form, and it's a little easier than the elimination method.

First, I will substitute the first equation, for y, into the second equation:

y = 4x + 9

y = 2x + 5

4x + 9 = 2x + 5

Next, subtract 2x from both sides to isolate x:

4x + 9 = 2x + 5

-2x      -2x

2x + 9 = 5

Then, subtract 9 from both sides:

2x + 9 = 5

     - 9  - 9

2x = -4

Now, divide both sides by 2:

2x = -4

/2    /2

x = -2

Now, we find the value of y, by substituting -2 for x:

y = 2x + 5

y = 2(-2) + 5

y = -4 + 5

y = 1

(x, y) ==> (-2, 1)

Check your answer using (-2, 1):

y = 2x + 5

1 = 2(-2) + 5

1 = -4 + 5

1 = 1

This statment is correct

y = 4x + 9

1 = 4(-2) + 9

1 = -8 + 9

1 = 1

This statment is also correct

Check your answer using  (-6, -7):

y = 2x + 5

-7 = 2(-6) + 5

-7 = -12 + 5

-7 = -7

This statment is correct

y = 4x + 9

-7 = 4(-6) + 9

-7 = -24 + 9

-7 = -15

This statment is NOT correct

Therefore, no (-6,-7) is NOT a solution to this system of equations.

*View the attached graph to check your answer graphically.*

Hope this helps!

View image Esther
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.