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How many moles of neon gas are there 25.0 L of gas or 5.0°C with a pressure of 89.9 KPa?

Sagot :

  • Volume=25L
  • Temperature=5°C
  • Pressure=89.9kPa

Now

[tex]\\ \rm\rightarrowtail PV=nRT[/tex]

[tex]\\ \rm\rightarrowtail n=\dfrac{PV}{RT}[/tex]

[tex]\\ \rm\rightarrowtail n=\dfrac{89.9(25)}{5R}[/tex]

[tex]\\ \rm\rightarrowtail n=89.9(5)/R[/tex]

[tex]\\ \rm\rightarrowtail n=449.5/R mol[/tex]

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