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Given the equation, what is the center and radius of the circle?

(x-7) ^2 + (Y-4) ^2= 64 ^2

Sagot :

We are given the equation of circle (x - 7)² + (y - 3)² = 64² , but let's recall the standard equation of circle i.e (x - h)² + (y - k)² = r², where (h, k) is the centre of the circle and r being the radius ;

So, consider the equation of circle ;

[tex]{:\implies \quad \sf (x-7)^{2}+(y-4)^{2}=(64)^{2}}[/tex]

On comparing this equation with the standard equation of Circle, we will get, centre and radius as follows

  • Centre = (7, 4)
  • Radius = 64 units
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