Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

separate into real and imaginary parts and find the multiplicative inverse of √2+i/√2-i (only 2 is in the √

Sagot :

samuelonum1

The multiplicative inverse for √2-i = 1/(√2+1) and  The multiplicative inverse is √2+1 = 1/(√2-1)

Real and Imaginary Numbers/Complex Numbers

Given Data

  • First expression = √2+i
  • Second expression = √2-i

For√2+i

the real part is  is √2 and the imaginary part is i

The multiplicative inverse is √2+1 = 1/(√2-1)

rationalising the denominator we have

= 1/√2-1 * √2-1/√2-1

= √2-1/(√2-1)*(√2-1)

= √2-1/(2-√2-√2+1)

= √2-1/(-2√2+3)

For√2-i

the real part is  is √2 and the imaginary part is -i

The multiplicative inverse is √2-1 = 1/(√2+1)

Rationalising the denominator we have

= 1/√2+1 * √2+1/√2+1

= √2+1/(√2+1)*(√2+1)

= √2+1/(2+√2+√2+1)

= √2+1/(2√2+3)

Learn more about complex Numbers here

https://brainly.com/question/10662770

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.