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The nth term of a sequence is n2 + 5 (a) (i) Find the first two terms of this sequence. (ii) Is 126 a term of this sequence? You must show how you get your answer​

Sagot :

Answer:

126 is a term in the sequence.  Please check my assumption on the correct formula.

Step-by-step explanation:

I will assume that n2 + 5 is actually n^2 + 5.

Starting with n=0, use the formula to calculate successive values of n.  The attached table is the result of n from 0 to 22.  At n=11, the result is 126, so 126 is a term in the sequence.

If the expression is actually n2 + 5, calculate the values for y = 2n + 5.  126 would not be a term in this sequence.

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