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Sagot :
Answer:
k=2
Step-by-step explanation:
[tex](k + 2) {}^{2} - (k - 2)x - 5 = 0[/tex]
If we have two zeroes that are equal in size, but different signs then we have a different of squares,
[tex](a + b)(a - b) = {a}^{2} - b {}^{2} [/tex]
So in order to do this we must make the middle term, x 0 so
[tex]k - 2 = 0[/tex]
[tex]k = 2[/tex]
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