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Sagot :
Answer:
Step-by-step explanation:
h = -5t^2 - 6t + 44
I'll assume 0 meters is the ground height. That would mean we want to know the time, t, for h to be = 0 meters:
h = -5t^2 - 6t + 44
0 = -5t^2 - 6t + 44
5t^2 + 6t -44 = 0
Solve using the quadratic equation: 2.43 and - 3.63 seconds. We'll use the positive value: 2.43 seconds for the ball to reach the ground. Save the -3.63 value for the Klingons.
We can also solve by graphing the function, as per the attached image. Note that the starting time of 0 seconds, the ball is at 44 feet. It reaches the x axis at 2.43 seconds (where x = 0, the ground).
Answer:
t = 2.43 s (nearest hundredth)
Step-by-step explanation:
Given equation: [tex]h=44-6t-5t^2[/tex]
where:
- h = height (in meters)
- t = time (in seconds)
When the ball hits the ground, h = 0
[tex]\implies 44-6t-5t^2=0[/tex]
[tex]\implies 5t^2+6t-44=0[/tex]
Using the quadratic formula when [tex]ax^2+bx+c=0[/tex] and where:
- a = 5
- b = 6
- c = -44
- x = t
[tex]t=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
[tex]=\dfrac{-(6)\pm\sqrt{(6)^2-4(5)(-44)}}{2(5)}[/tex]
[tex]=\dfrac{-6\pm\sqrt{916}}{10}[/tex]
[tex]=\dfrac{-6\pm2\sqrt{229}}{10}[/tex]
[tex]=\dfrac{-3\pm\sqrt{229}}{5}[/tex]
[tex]=2.43, -3.63 \ \textsf{(nearest hundredth)}[/tex]
As time is positive, t = 2.43 s (nearest hundredth)
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