Answered

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Write the log equation as an exponential equation. You do not need to solve for x.
In (3x + 2) = 3x

Sagot :

loneguy

[tex]\ln(3x+2) = 3x\\\\\implies \log_e (3x+2) = 3x\\\\\implies e^{3x} = 3x+2[/tex]

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